What is the h(t)=-0.3(t^4-24t^3+189t^2-490t) ?

The h(t)=-0.3(t^4-24t^3+189t^2-490t) is

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h(t)=-0.3(t^4-24t^3+189t^2-490t)

h (t) = - 0.3 (t^{4} - 24 t^{3} + 189 t^{2} - 490 t)

Domain : - \infty < t < \infty

Range : f (t) \leq 120.10692 \dots

X Intercepts : (0, 0), (7, 0), (10, 0), Y Intercepts : (0, 0)

Asymptotes : None

Extreme Points : Maximum (\frac{11 - 51}{2}, 120.10692 \dots), Minimum (7, 0), Maximum (\frac{11 + 51}{2}, 10.84307 \dots)

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, 120.10692 \dots]

Solution steps

Domain of

- 0.3 (t^{4} - 24 t^{3} + 189 t^{2} - 490 t) : - \infty < t < \infty

Range of

- 0.3 (t^{4} - 24 t^{3} + 189 t^{2} - 490 t) : f (t) \leq 120.10692 \dots

Axis interception points of

- 0.3 (t^{4} - 24 t^{3} + 189 t^{2} - 490 t) :

X Intercepts

: (0, 0), (7, 0), (10, 0),

Y Intercepts

: (0, 0)

Asymptotes of

- 0.3 (t^{4} - 24 t^{3} + 189 t^{2} - 490 t) :

None

Extreme Points of

- 0.3 (t^{4} - 24 t^{3} + 189 t^{2} - 490 t) :

Maximum

(\frac{11 - 51}{2}, 120.10692 \dots),

Minimum

(7, 0),

Maximum

(\frac{11 + 51}{2}, 10.84307 \dots)

g (x) = (\frac{1}{2} x)^{2}

f (x) = x^{4} - x^{2} - 2

f (x) = x^{4} - x^{2} + 5

y = x^{2} - 4 x - 165

f (y) = 60 y^{12}

What is the h(t)=-0.3(t^4-24t^3+189t^2-490t) ?
The h(t)=-0.3(t^4-24t^3+189t^2-490t) is