What is the domain of f(x)=((x^2-1))/((x+1)) ?

The domain of f(x)=((x^2-1))/((x+1)) is x -1

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domain of f(x)=((x^2-1))/((x+1))

domain

f (x) = \frac{( x ^{2} - 1 )}{( x + 1 )}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = - x^{3} - 3 x^{2} + 9 x + 1

y = - x^{2} - 3

\frac{3 x ^{2}}{2 x + 2}

f (x) = \frac{1}{2 - x}

f (x) = 2 x e^{5 x}

What is the domain of f(x)=((x^2-1))/((x+1)) ?
The domain of f(x)=((x^2-1))/((x+1)) is x<-1\lor x>-1