What is the domain of f(x)=\sqrt[3]{1+4x} ?

The domain of f(x)=\sqrt[3]{1+4x} is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{1+4x}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

P (a) = a^{5} + a + 1

F (x) = x^{2} - 2 x + 1

f (x) = - 2 (x + 3)^{2} - 4

f (x) = x^{2} - 6 x + 24

f (x) = - x^{8}

What is the domain of f(x)=\sqrt[3]{1+4x} ?
The domain of f(x)=\sqrt[3]{1+4x} is -infinity <x<infinity