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Popular >

f(n)=sqrt(n^2+n)-n

Solution

f (n) = n^{2} + n - n

Solution

Domain : n \leq - 1 or n \geq 0

Range : 0 \leq f (x) < \frac{1}{2} or f (x) \geq 1

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Horizontal y = \frac{1}{2}, Slant y = - 2 n - \frac{1}{2}

Extreme Points : Minimum (- 1, 1), Minimum (0, 0)

+1

Interval Notation

Domain : (- \infty, - 1] \cup [0, \infty)

Range : [0, \frac{1}{2}) \cup [1, \infty)

Solution steps

Domain of

n^{2} + n - n : n \leq - 1 or n \geq 0

Range of

n^{2} + n - n : 0 \leq f (x) < \frac{1}{2} or f (x) \geq 1

Axis interception points of

n^{2} + n - n :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

n^{2} + n - n :

Horizontal

: y = \frac{1}{2},

Slant

: y = - 2 n - \frac{1}{2}

Extreme Points of

n^{2} + n - n :

Minimum

(- 1, 1),

Minimum

(0, 0)

Popular Examples

f(x)=3+sqrt(x-2)

f (x) = 3 + x - 2

f(x)=e^{-(x-2)}-1

f (x) = e^{- (x - 2)} - 1

f(x)=sin(x^2+3x-2)

f (x) = sin (x^{2} + 3 x - 2)

f (x) = 2^{3} - x

y=sqrt(x/2)+sqrt(2/x)

y = \frac{x}{2} + \frac{2}{x}

Frequently Asked Questions (FAQ)

What is the f(n)=sqrt(n^2+n)-n ?
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