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Popular >

y=(2x^2-3x+9)/(7-5x)

Solution

y = \frac{2 x ^{2} - 3 x + 9}{7 - 5 x}

Solution

Domain : x < \frac{7}{5} or x > \frac{7}{5}

Range : f (x) \leq \frac{- 4 109 - 13}{25} or f (x) \geq \frac{4 109 - 13}{25}

Y Intercepts : (0, \frac{9}{7})

Asymptotes : Vertical x = \frac{7}{5}, Slant y = - \frac{2}{5} x + \frac{1}{25}

Extreme Points : Minimum (- \frac{- 7 + 109}{5}, \frac{436 - 13 109}{25 109}), Maximum (\frac{7 + 109}{5}, - \frac{436 + 13 109}{25 109})

+1

Interval Notation

Domain : (- \infty, \frac{7}{5}) \cup (\frac{7}{5}, \infty)

Range : (- \infty, \frac{- 4 109 - 13}{25}] \cup [\frac{4 109 - 13}{25}, \infty)

Solution steps

Domain of

\frac{2 x ^{2} - 3 x + 9}{7 - 5 x} : x < \frac{7}{5} or x > \frac{7}{5}

Range of

\frac{2 x ^{2} - 3 x + 9}{7 - 5 x} : f (x) \leq \frac{- 4 109 - 13}{25} or f (x) \geq \frac{4 109 - 13}{25}

Axis interception points of

\frac{2 x ^{2} - 3 x + 9}{7 - 5 x} :

Y Intercepts

: (0, \frac{9}{7})

Asymptotes of

\frac{2 x ^{2} - 3 x + 9}{7 - 5 x} :

Vertical

: x = \frac{7}{5},

Slant

: y = - \frac{2}{5} x + \frac{1}{25}

Extreme Points of

\frac{2 x ^{2} - 3 x + 9}{7 - 5 x} :

Minimum

(- \frac{- 7 + 109}{5}, \frac{436 - 13 109}{25 109}),

Maximum

(\frac{7 + 109}{5}, - \frac{436 + 13 109}{25 109})

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C(x)=x^2+10x+120

C (x) = x^{2} + 10 x + 120

Frequently Asked Questions (FAQ)

What is the y=(2x^2-3x+9)/(7-5x) ?
The y=(2x^2-3x+9)/(7-5x) is