What is the f(n)=\sqrt[2n]{\sqrt[n]{3n^2}} ?

The f(n)=\sqrt[2n]{\sqrt[n]{3n^2}} is

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f(n)=\sqrt[2n]{\sqrt[n]{3n^2}}

f (n) = 2 n n 3 n^{2}

Domain : n < 0 or n > 0

Intercepts : None

Extreme Points : Maximum (- 4 \frac{e ^{2}}{9}, (e^{\frac{3}{e}})^{\frac{1}{1.90377 \dots}}), Maximum (4 \frac{e ^{2}}{9}, 1.90377 \dots e^{\frac{3}{e}})

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Solution steps

Domain of

2 n n 3 n^{2} : n < 0 or n > 0

Axis interception points of

2 n n 3 n^{2} :

None

Extreme Points of

2 n n 3 n^{2} :

Maximum

(- 4 \frac{e ^{2}}{9}, (e^{\frac{3}{e}})^{\frac{1}{1.90377 \dots}}),

Maximum

(4 \frac{e ^{2}}{9}, 1.90377 \dots e^{\frac{3}{e}})

f (x) = \frac{3 tan ( x ) + 2 sec ( x )}{2 tan ( x ) + 3 sec ( x )}

f (x) = lo g_{\frac{4}{5}} (x)

f (x) = sinh (6 x)

f (x) = 2 lo g_{10} (x + 2) + 1

f (x) = 3 x^{2} + x - 7

What is the f(n)=\sqrt[2n]{\sqrt[n]{3n^2}} ?
The f(n)=\sqrt[2n]{\sqrt[n]{3n^2}} is