What is the general solution for solvefor y,y=(cos(2θ))/(1-sin(2θ)) ?

The general solution for solvefor y,y=(cos(2θ))/(1-sin(2θ)) is y=(cos(2θ))/(1-sin(2θ))

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solvefor y,y=(cos(2θ))/(1-sin(2θ))

solve for

y, y = \frac{cos ( 2 θ )}{1 - sin ( 2 θ )}

y = \frac{cos ( 2 θ )}{1 - sin ( 2 θ )}

Solution steps

y = \frac{cos ( 2 θ )}{1 - sin ( 2 θ )}

Could not simplify further

y = \frac{cos ( 2 θ )}{1 - sin ( 2 θ )}

f (x) = - 6 x + 8

h (x) = x - 7 + 5

f (x) = - 2 x^{2} - 6 x - 7

f (x) = 18 sin^{4} (x)

f (x) = \frac{2 - sin ( x )}{2 + cos ( x )}

What is the general solution for solvefor y,y=(cos(2θ))/(1-sin(2θ)) ?
The general solution for solvefor y,y=(cos(2θ))/(1-sin(2θ)) is y=(cos(2θ))/(1-sin(2θ))