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Popular >

y=x^3+2x^2-1

Solution

y = x^{3} + 2 x^{2} - 1

Solution

Domain : - \infty < x < \infty

Range : - \infty < f (x) < \infty

X Intercepts : (- 1, 0), (\frac{- 1 + 5}{2}, 0), (\frac{- 1 - 5}{2}, 0), Y Intercepts : (0, - 1)

Asymptotes : None

Extreme Points : Maximum (- \frac{4}{3}, \frac{5}{27}), Minimum (0, - 1)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

x^{3} + 2 x^{2} - 1 : - \infty < x < \infty

Range of

x^{3} + 2 x^{2} - 1 : - \infty < f (x) < \infty

Axis interception points of

x^{3} + 2 x^{2} - 1 :

X Intercepts

: (- 1, 0), (\frac{- 1 + 5}{2}, 0), (\frac{- 1 - 5}{2}, 0),

Y Intercepts

: (0, - 1)

Asymptotes of

x^{3} + 2 x^{2} - 1 :

None

Extreme Points of

x^{3} + 2 x^{2} - 1 :

Maximum

(- \frac{4}{3}, \frac{5}{27}),

Minimum

(0, - 1)

Popular Examples

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f (t) = {t^{2} e^{- 2 t} : t \geq 0, 0 : t < 0}

f(x)=log_{1/5}(x^2-x-12)

f (x) = lo g_{\frac{1}{5}} (x^{2} - x - 12)

y=sin(x-pi/2)+1

y = sin (x - \frac{π}{2}) + 1

f(j)=(5j^3+6j^2)^4

f (j) = (5 j^{3} + 6 j^{2})^{4}

f(x)=-(x^2-9)(x+1)(2x-5)

f (x) = - (x^{2} - 9) (x + 1) (2 x - 5)

Frequently Asked Questions (FAQ)

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