What is the f(x)=(-6x\sqrt[5]{2x+6})/(log_{10)(x+2)} ?

The f(x)=(-6x\sqrt[5]{2x+6})/(log_{10)(x+2)} is

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f(x)=(-6x\sqrt[5]{2x+6})/(log_{10)(x+2)}

Domain : - 2 < x < - 1 or x > - 1

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = - 1

Extreme Points : None

Interval Notation

Domain : (- 2, - 1) \cup (- 1, \infty)

Solution steps

Domain of

Axis interception points of

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

Vertical

: x = - 1

Extreme Points of

None

f (x) = 2 sin^{2} (3 x)

f (x) = - \frac{1}{2} x + 5

f (x) = - 4 - x^{2}, 0 \leq x < 2

f (x) = 4 x^{2} + 4 x - 4

f (x) = x + 5 - 4

What is the f(x)=(-6x\sqrt[5]{2x+6})/(log_{10)(x+2)} ?
The f(x)=(-6x\sqrt[5]{2x+6})/(log_{10)(x+2)} is