What is the Q(z)=(z+1)/(arctan(z)) ?

The Q(z)=(z+1)/(arctan(z)) is Domain: z 0 Intercepts: None Asymptotes: Vertical z=0

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Q(z)=(z+1)/(arctan(z))

Q (z) = \frac{z + 1}{arctan ( z )}

Domain : z < 0 or z > 0

Intercepts : None

Asymptotes : Vertical z = 0

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Solution steps

Domain of

\frac{z + 1}{arctan ( z )} : z < 0 or z > 0

Axis interception points of

\frac{z + 1}{arctan ( z )} :

None

Asymptotes of

\frac{z + 1}{arctan ( z )} :

Vertical

: z = 0

f (x) = \frac{9 x ^{2} + 7}{x + 7}

f (x) = - 3 x^{2} - 30 x - 73

f (x) = \frac{x}{7} + \frac{7}{x}

f (x) = x^{3} - 12 x^{2} + 35 x

y = (x^{2} + 1) (x^{3} + 1)

What is the Q(z)=(z+1)/(arctan(z)) ?
The Q(z)=(z+1)/(arctan(z)) is Domain: z<0\lor z>0<br/>Intercepts: None<br/>Asymptotes: Vertical z=0