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Popular >

f(y)=y^4+4y^3+8y^2+9y+6

Solution

f (y) = y^{4} + 4 y^{3} + 8 y^{2} + 9 y + 6

Solution

Domain : - \infty < y < \infty

Range : f (y) \geq 1.87849 \dots

Y Intercepts : (0, 6)

Asymptotes : None

Extreme Points : Minimum (- 1.23673 \dots, 1.87849 \dots)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [1.87849 \dots, \infty)

Solution steps

Domain of

y^{4} + 4 y^{3} + 8 y^{2} + 9 y + 6 : - \infty < y < \infty

Range of

y^{4} + 4 y^{3} + 8 y^{2} + 9 y + 6 : f (y) \geq 1.87849 \dots

Axis interception points of

y^{4} + 4 y^{3} + 8 y^{2} + 9 y + 6 :

Y Intercepts

: (0, 6)

Asymptotes of

y^{4} + 4 y^{3} + 8 y^{2} + 9 y + 6 :

None

Extreme Points of

y^{4} + 4 y^{3} + 8 y^{2} + 9 y + 6 :

Minimum

(- 1.23673 \dots, 1.87849 \dots)

Popular Examples

f(x)=(x^3)/3+(x^2)/2-6x+8

f (x) = \frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 6 x + 8

f(t)=9t^3-18t^2+6t

f (t) = 9 t^{3} - 18 t^{2} + 6 t

f(t)=e^{-2t}+e^{2t}

f (t) = e^{- 2 t} + e^{2 t}

f(x)=(6x+8)+(12x-8)

f (x) = (6 x + 8)^{\circ} + (12 x - 8)^{\circ}

f(x)= 1/(arctanh(x))

f (x) = \frac{1}{arctanh ( x )}

Frequently Asked Questions (FAQ)

What is the f(y)=y^4+4y^3+8y^2+9y+6 ?
The f(y)=y^4+4y^3+8y^2+9y+6 is