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Popular >

f(y)=yln(1+e^y)

Solution

f (y) = y ln (1 + e^{y})

Solution

Domain : - \infty < y < \infty

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Horizontal y = 0

Inflection Points : (- W_{0} (\frac{2}{e ^{2}}) - 2, ln (1 + e^{- W_{0} (\frac{2}{e ^{2}}) - 2}) (- W_{0} (\frac{2}{e ^{2}}) - 2))

+1

Interval Notation

Domain : (- \infty, \infty)

Solution steps

Domain of

y ln (1 + e^{y}) : - \infty < y < \infty

Axis interception points of

y ln (1 + e^{y}) :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

y ln (1 + e^{y}) :

Horizontal

: y = 0

Inflection Points of

y ln (1 + e^{y}) : (- W_{0} (\frac{2}{e ^{2}}) - 2, ln (1 + e^{- W_{0} (\frac{2}{e ^{2}}) - 2}) (- W_{0} (\frac{2}{e ^{2}}) - 2))

Graph

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Frequently Asked Questions (FAQ)

What is the f(y)=yln(1+e^y) ?
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