What is the f(t)=2cos(t)+sin(2t),0<= t<= pi/2 ?

The f(t)=2cos(t)+sin(2t),0<= t<= pi/2 is

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f(t)=2cos(t)+sin(2t),0<= t<= pi/2

f (t) = 2 cos (t) + sin (2 t), 0 \leq t \leq \frac{π}{2}

Period : 2 π

Domain : 0 \leq t \leq \frac{π}{2}

Range : 0 \leq f (t) \leq 3 + \frac{3}{2}

X Intercepts : (\frac{π}{2}, 0), Y Intercepts : (0, 2)

Asymptotes : None

Extreme Points : Minimum (0, 2), Maximum (\frac{π}{6}, 3 + \frac{3}{2}), Minimum (\frac{π}{2}, 0)

Interval Notation

Domain : [0, \frac{π}{2}]

Range : [0, 3 + \frac{3}{2}]

Solution steps

Periodicity of

2 cos (t) + sin (2 t) : 2 π

Domain of

2 cos (t) + sin (2 t), 0 \leq t \leq \frac{π}{2} : 0 \leq t \leq \frac{π}{2}

Range of

2 cos (t) + sin (2 t), 0 \leq t \leq \frac{π}{2} : 0 \leq f (t) \leq 3 + \frac{3}{2}

Axis interception points of

2 cos (t) + sin (2 t), 0 \leq t \leq \frac{π}{2} :

X Intercepts

: (\frac{π}{2}, 0),

Y Intercepts

: (0, 2)

Asymptotes of

2 cos (t) + sin (2 t), 0 \leq t \leq \frac{π}{2} :

None

Extreme Points of

2 cos (t) + sin (2 t), 0 \leq t \leq \frac{π}{2} :

Minimum

(0, 2),

Maximum

(\frac{π}{6}, 3 + \frac{3}{2}),

Minimum

(\frac{π}{2}, 0)

f (x) = \frac{1}{2} e^{x^{2}} + sin (x)

f (x) = 1 + 2 x + 3 x^{2} + 4 x^{3}

y = 3 cos (x) + 3

f (m) = \frac{1}{m}

f (x) = x^{2} - 16 x + 28

What is the f(t)=2cos(t)+sin(2t),0<= t<= pi/2 ?
The f(t)=2cos(t)+sin(2t),0<= t<= pi/2 is