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Popular >

h(t)=sqrt((t+1)/(3t+4))

Solution

h (t) = \frac{t + 1}{3 t + 4}

Solution

Domain : t < - \frac{4}{3} or t \geq - 1

X Intercepts : (- 1, 0), Y Intercepts : (0, \frac{1}{2})

Asymptotes : Horizontal y = \frac{1}{3}

Extreme Points : Minimum (- 1, 0)

+1

Interval Notation

Domain : (- \infty, - \frac{4}{3}) \cup [- 1, \infty)

Solution steps

Domain of

\frac{t + 1}{3 t + 4} : t < - \frac{4}{3} or t \geq - 1

Axis interception points of

\frac{t + 1}{3 t + 4} :

X Intercepts

: (- 1, 0),

Y Intercepts

: (0, \frac{1}{2})

Asymptotes of

\frac{t + 1}{3 t + 4} :

Horizontal

: y = \frac{1}{3}

Extreme Points of

\frac{t + 1}{3 t + 4} :

Minimum

(- 1, 0)

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P (x) = 4 x^{2} + (14) x + (49)

f(x)=3x^3+4x^2+7x-12

f (x) = 3 x^{3} + 4 x^{2} + 7 x - 12

y= 1/4 (x-2)^2+6

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f(x)=(8x^2+16x-64)/(x^2)

f (x) = \frac{8 x ^{2} + 16 x - 64}{x ^{2}}

Frequently Asked Questions (FAQ)

What is the h(t)=sqrt((t+1)/(3t+4)) ?
The h(t)=sqrt((t+1)/(3t+4)) is