What is the f(t)={e^{2t}:0<t<3,1:3<t} ?

The f(t)={e^{2t}:0<t<3,1:3<t} is

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f(t)={e^{2t}:0<t<3,1:3<t}

f (t) = {e^{2 t} : 0 < t < 3, 1 : 3 < t}

Domain : 0 < t < 3 or t > 3

Intercepts : None

Asymptotes : Horizontal y = 1

Monotone Intervals : Increasing : 0 < t < 3, Constant : 3 < t < \infty

Interval Notation

Domain : (0, 3) \cup (3, \infty)

Solution steps

Domain of

{e^{2 t} : 0 < t < 3, 1 : t > 3} : 0 < t < 3 or t > 3

Axis interception points of

{e^{2 t} : 0 < t < 3, 1 : t > 3} :

None

Asymptotes of

{e^{2 t} : 0 < t < 3, 1 : t > 3} :

Horizontal

: y = 1

Monotone Intervals of

{e^{2 t} : 0 < t < 3, 1 : t > 3} :

Increasing

: 0 < t < 3,

Constant

: 3 < t < \infty

f (x) = 3 x^{2} - 18 x + 100

f (x) = 2 x^{3} + 2 x^{2} - x

f (x) = x^{6} - 5 x^{3} + 6

y = (x - 2) (x - 5)

y = - 3 x^{2} + 4 x - 1