What is the p(t)=(19.875)/((1+57.993e^{-0.035005t))} ?

The p(t)=(19.875)/((1+57.993e^{-0.035005t))} is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

p(t)=(19.875)/((1+57.993e^{-0.035005t))}

p (t) = \frac{19.875}{( 1 + 57.993 e ^{- 0.035005 t} )}

Domain : - \infty < t < \infty

Range : 0 < f (t) < 19.875

Y Intercepts : (0, \frac{19.875}{58.993})

Asymptotes : Horizontal y = 19.875, y = 0

Extreme Points : None

Interval Notation

Domain : (- \infty, \infty)

Range : (0, 19.875)

Solution steps

Domain of

\frac{19.875}{1 + 57.993 e ^{- 0.035005 t}} : - \infty < t < \infty

Range of

\frac{19.875}{1 + 57.993 e ^{- 0.035005 t}} : 0 < f (t) < 19.875

Axis interception points of

\frac{19.875}{1 + 57.993 e ^{- 0.035005 t}} :

Y Intercepts

: (0, \frac{19.875}{58.993})

Asymptotes of

\frac{19.875}{1 + 57.993 e ^{- 0.035005 t}} :

Horizontal

: y = 19.875, y = 0

Extreme Points of

\frac{19.875}{1 + 57.993 e ^{- 0.035005 t}} :

None

g (x) = lo g_{5} (\frac{x + 1}{x})

f (x) = \frac{3}{2 - x ^{2}}

f (x) = \frac{x ^{3} + 7 x ^{2} - 5 x + 4}{x ^{2}}

y = cos (x + \frac{π}{2}) + 1

f (x) = \frac{x + 8}{x ^{2} + 64}

What is the p(t)=(19.875)/((1+57.993e^{-0.035005t))} ?
The p(t)=(19.875)/((1+57.993e^{-0.035005t))} is