What is the domain of\&range f(x)=sqrt(-x^2+6*x) ?

The domain of\&range f(x)=sqrt(-x^2+6*x) is Domain: 0 Range: 0<= f(x)<= 3

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domain of\&range f(x)=sqrt(-x^2+6*x)

domain and range

f (x) = - x^{2} + 6 \cdot x

Domain : 0 \leq x \leq 6

Range : 0 \leq f (x) \leq 3

Interval Notation

Domain : [0, 6]

Range : [0, 3]

Solution steps

Domain of

- x^{2} + 6 \cdot x : 0 \leq x \leq 6

Range of

- x^{2} + 6 \cdot x : 0 \leq f (x) \leq 3

f (\frac{x ^{2} - 1}{x ^{2} + 1}) = x

y = 7 x^{2} + 2 x

f (x) = lo g_{10} (- 3 x)

y = \frac{1}{3} sin (2 x)

f (t) = \frac{cos ( 2 t ) - 1}{2}

What is the domain of\&range f(x)=sqrt(-x^2+6*x) ?
The domain of\&range f(x)=sqrt(-x^2+6*x) is Domain: 0<= x<= 6<br/>Range: 0<= f(x)<= 3