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Popular >

g(x)= x/(x^2+64)

Solution

g (x) = \frac{x}{x ^{2} + 64}

Solution

Domain : - \infty < x < \infty

Range : - \frac{1}{16} \leq f (x) \leq \frac{1}{16}

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Horizontal y = 0

Extreme Points : Minimum (- 8, - \frac{1}{16}), Maximum (8, \frac{1}{16})

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{1}{16}, \frac{1}{16}]

Solution steps

Domain of

\frac{x}{x ^{2} + 64} : - \infty < x < \infty

Range of

\frac{x}{x ^{2} + 64} : - \frac{1}{16} \leq f (x) \leq \frac{1}{16}

Axis interception points of

\frac{x}{x ^{2} + 64} :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{x}{x ^{2} + 64} :

Horizontal

: y = 0

Extreme Points of

\frac{x}{x ^{2} + 64} :

Minimum

(- 8, - \frac{1}{16}),

Maximum

(8, \frac{1}{16})

Graph

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f (x) = \frac{1}{8 + x}

h(x)=(x^2+5)/(x-1)

h (x) = \frac{x ^{2} + 5}{x - 1}

Frequently Asked Questions (FAQ)

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