What is the f(x)=((3x^3+2x^2-12x+4))/((x^2)) ?

The f(x)=((3x^3+2x^2-12x+4))/((x^2)) is

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f(x)=((3x^3+2x^2-12x+4))/((x^2))

f (x) = \frac{( 3 x ^{3} + 2 x ^{2} - 12 x + 4 )}{( x ^{2} )}

Domain : x < 0 or x > 0

Range : - \infty < f (x) < \infty

X Intercepts : (0.36846 \dots, 0), (1.45384 \dots, 0), (- 2.48897 \dots, 0)

Asymptotes : Vertical x = 0, Slant y = 3 x + 2

Extreme Points : Minimum (0.60993 \dots, - 5.09233 \dots)

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{3 x ^{3} + 2 x ^{2} - 12 x + 4}{x ^{2}} : x < 0 or x > 0

Range of

\frac{3 x ^{3} + 2 x ^{2} - 12 x + 4}{x ^{2}} : - \infty < f (x) < \infty

Axis interception points of

\frac{3 x ^{3} + 2 x ^{2} - 12 x + 4}{x ^{2}} :

X Intercepts

: (0.36846 \dots, 0), (1.45384 \dots, 0), (- 2.48897 \dots, 0)

Asymptotes of

\frac{3 x ^{3} + 2 x ^{2} - 12 x + 4}{x ^{2}} :

Vertical

: x = 0,

Slant

: y = 3 x + 2

Extreme Points of

\frac{3 x ^{3} + 2 x ^{2} - 12 x + 4}{x ^{2}} :

Minimum

(0.60993 \dots, - 5.09233 \dots)

y = ln (3 - 2 x)

f (t) = 2 t^{2} - 3 t + 2

f (x) = lo g_{3} (sin (x^{2}))

f (t) = 6 t + 5

f (x) = 5 sin (x) + 2

What is the f(x)=((3x^3+2x^2-12x+4))/((x^2)) ?
The f(x)=((3x^3+2x^2-12x+4))/((x^2)) is