What is the f(x)=(x^2(x-2))/((x-3)^2(x+1)) ?

The f(x)=(x^2(x-2))/((x-3)^2(x+1)) is

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f(x)=(x^2(x-2))/((x-3)^2(x+1))

f (x) = \frac{x ^{2} ( x - 2 )}{( x - 3 ) ^{2} ( x + 1 )}

Domain : x < - 1 or - 1 < x < 3 or x > 3

Range : - \infty < f (x) < \infty

X Intercepts : (0, 0), (2, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = - 1, x = 3, Horizontal y = 1

Extreme Points : Minimum (- \frac{1 + 17}{2}, \frac{107 + 51 17}{512}), Maximum (0, 0), Minimum (\frac{17 - 1}{2}, \frac{107 - 51 17}{512})

Interval Notation

Domain : (- \infty, - 1) \cup (- 1, 3) \cup (3, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{x ^{2} ( x - 2 )}{( x - 3 ) ^{2} ( x + 1 )} : x < - 1 or - 1 < x < 3 or x > 3

Range of

\frac{x ^{2} ( x - 2 )}{( x - 3 ) ^{2} ( x + 1 )} : - \infty < f (x) < \infty

Axis interception points of

\frac{x ^{2} ( x - 2 )}{( x - 3 ) ^{2} ( x + 1 )} :

X Intercepts

: (0, 0), (2, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{x ^{2} ( x - 2 )}{( x - 3 ) ^{2} ( x + 1 )} :

Vertical

: x = - 1, x = 3,

Horizontal

: y = 1

Extreme Points of

\frac{x ^{2} ( x - 2 )}{( x - 3 ) ^{2} ( x + 1 )} :

Minimum

(- \frac{1 + 17}{2}, \frac{107 + 51 17}{512}),

Maximum

(0, 0),

Minimum

(\frac{17 - 1}{2}, \frac{107 - 51 17}{512})

f (t) = sin (t) d t

f (x) = 2 x - 3 - 2 (5 x - 4)

f (n) = \frac{2 n ^{3} + 3 n ^{2} + n}{3}

f (x) = x^{3} + 5 x + 1

s (t) = t^{3} (\frac{2}{t} - \frac{3}{t ^{2}})^{2}

What is the f(x)=(x^2(x-2))/((x-3)^2(x+1)) ?
The f(x)=(x^2(x-2))/((x-3)^2(x+1)) is