What is the extreme S(r)=2pirh+2pir^2 ?

The extreme S(r)=2pirh+2pir^2 is Saddle(0,0)

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extreme S(r)=2pirh+2pir^2

extreme points

S (r) = 2 π r h + 2 π r^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial r ^{2}} = 0

D (r, h) = - 4 π^{2}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = ln (x^{4} + 1)

f (x) = \frac{x ^{\frac{5}{3}}}{2 + x}

f (x) = \frac{x - 5}{5}

y = 1000 \cdot (0.9)^{x}

What is the extreme S(r)=2pirh+2pir^2 ?
The extreme S(r)=2pirh+2pir^2 is Saddle(0,0)