What is the f(x)=(1/3)x^3-(1/6)x^2-(2/3)x ?

The f(x)=(1/3)x^3-(1/6)x^2-(2/3)x is

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f(x)=(1/3)x^3-(1/6)x^2-(2/3)x

f (x) = (\frac{1}{3}) x^{3} - (\frac{1}{6}) x^{2} - (\frac{2}{3}) x

Domain : - \infty < x < \infty

Range : - \infty < f (x) < \infty

X Intercepts : (0, 0), (\frac{1 + 33}{4}, 0), (\frac{1 - 33}{4}, 0), Y Intercepts : (0, 0)

Asymptotes : None

Extreme Points : Maximum (- \frac{2}{3}, \frac{22}{81}), Minimum (1, - \frac{1}{2})

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{1}{3} x^{3} - \frac{1}{6} x^{2} - \frac{2}{3} x : - \infty < x < \infty

Range of

\frac{1}{3} x^{3} - \frac{1}{6} x^{2} - \frac{2}{3} x : - \infty < f (x) < \infty

Axis interception points of

\frac{1}{3} x^{3} - \frac{1}{6} x^{2} - \frac{2}{3} x :

X Intercepts

: (0, 0), (\frac{1 + 33}{4}, 0), (\frac{1 - 33}{4}, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{1}{3} x^{3} - \frac{1}{6} x^{2} - \frac{2}{3} x :

None

Extreme Points of

\frac{1}{3} x^{3} - \frac{1}{6} x^{2} - \frac{2}{3} x :

Maximum

(- \frac{2}{3}, \frac{22}{81}),

Minimum

(1, - \frac{1}{2})

y = \frac{x + 3}{x}

f (y) = \frac{2 y ^{2} + 3 y - 7}{y}

f (x) = 4 x^{2}

f (x) = 2 x^{2} - x - 7

f (x) = 2 x^{2} - x + 8

What is the f(x)=(1/3)x^3-(1/6)x^2-(2/3)x ?
The f(x)=(1/3)x^3-(1/6)x^2-(2/3)x is