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Popular >

f(x)=0.5x^2+2x-16

Solution

f (x) = 0.5 x^{2} + 2 x - 16

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq - 18

X Intercepts : (4, 0), (- 8, 0), Y Intercepts : (0, - 16)

Vertex : Minimum (- 2, - 18)

Inverse : \frac{- 20 + 200 x + 3600}{10}, \frac{- 20 - 200 x + 3600}{10}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- 18, \infty)

Solution steps

Domain of

0.5 x^{2} + 2 x - 16 : - \infty < x < \infty

Range of

0.5 x^{2} + 2 x - 16 : f (x) \geq - 18

Axis interception points of

0.5 x^{2} + 2 x - 16 :

X Intercepts

: (4, 0), (- 8, 0),

Y Intercepts

: (0, - 16)

Vertex of

0.5 x^{2} + 2 x - 16 :

Minimum

(- 2, - 18)

Inverse of

0.5 x^{2} + 2 x - 16 : \frac{- 20 + 200 x + 3600}{10}, \frac{- 20 - 200 x + 3600}{10}

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Frequently Asked Questions (FAQ)

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