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Popular >

f(x)=ln(1+2x)-x^2

Solution

f (x) = ln (1 + 2 x) - x^{2}

Solution

Domain : x > - \frac{1}{2}

Range : f (x) \leq ln (2) - \frac{1}{4}

Y Intercepts : (0, 0)

Asymptotes : Vertical x = - \frac{1}{2}

Extreme Points : Maximum (\frac{1}{2}, ln (2) - \frac{1}{4})

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Solution steps

Domain of

ln (1 + 2 x) - x^{2} : x > - \frac{1}{2}

Range of

ln (1 + 2 x) - x^{2} : f (x) \leq ln (2) - \frac{1}{4}

Axis interception points of

ln (1 + 2 x) - x^{2} :

Y Intercepts

: (0, 0)

Asymptotes of

ln (1 + 2 x) - x^{2} :

Vertical

: x = - \frac{1}{2}

Extreme Points of

ln (1 + 2 x) - x^{2} :

Maximum

(\frac{1}{2}, ln (2) - \frac{1}{4})

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Frequently Asked Questions (FAQ)

What is the f(x)=ln(1+2x)-x^2 ?
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