What is the f(x)=(4x+6)/(sqrt(x^2+3x+4)) ?

The f(x)=(4x+6)/(sqrt(x^2+3x+4)) is

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f(x)=(4x+6)/(sqrt(x^2+3x+4))

f (x) = \frac{4 x + 6}{x ^{2} + 3 x + 4}

Domain : - \infty < x < \infty

Range : - 4 < f (x) < 4

X Intercepts : (- \frac{3}{2}, 0), Y Intercepts : (0, 3)

Asymptotes : Horizontal y = 4, y = - 4

Extreme Points : None

Solution steps

Domain of

\frac{4 x + 6}{x ^{2} + 3 x + 4} : - \infty < x < \infty

Range of

\frac{4 x + 6}{x ^{2} + 3 x + 4} : - 4 < f (x) < 4

Axis interception points of

\frac{4 x + 6}{x ^{2} + 3 x + 4} :

X Intercepts

: (- \frac{3}{2}, 0),

Y Intercepts

: (0, 3)

Asymptotes of

\frac{4 x + 6}{x ^{2} + 3 x + 4} :

Horizontal

: y = 4, y = - 4

Extreme Points of

\frac{4 x + 6}{x ^{2} + 3 x + 4} :

None

g (x) = ∣ x - 2 ∣ + ∣ x + 1 ∣

f (x) = cos (\frac{x}{6})

f (x) = 6 x^{3} - 9 x^{2} - 108 x

f (x) = - 2 x^{2} + \frac{1}{2}

f (w) = (\frac{w - 3}{w + 2})^{2}