What is the y=-0.00003x^2+0.0191x+0.1156 ?

The y=-0.00003x^2+0.0191x+0.1156 is

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y=-0.00003x^2+0.0191x+0.1156

y = - 0.00003 x^{2} + 0.0191 x + 0.1156

Domain : - \infty < x < \infty

Range : f (x) \leq 0

X Intercepts : (- \frac{- 0.0191 + 0.000378682}{0.00006}, 0), (\frac{0.0191 + 0.000378682}{0.00006}, 0), Y Intercepts : (0, 0.1156)

Vertex : Maximum (318.33333 \dots, 3.15568 \dots)

Inverse : - \frac{- 0.0191 + - 0.00012 x + 0.000378682}{0.00006}, - \frac{- 0.0191 - - 0.00012 x + 0.000378682}{0.00006}

Interval Notation

Domain : (- \infty, \infty)

Solution steps

Domain of

- 0.00003 x^{2} + 0.0191 x + 0.1156 : - \infty < x < \infty

Range of

- 0.00003 x^{2} + 0.0191 x + 0.1156 : f (x) \leq 0

Axis interception points of

- 0.00003 x^{2} + 0.0191 x + 0.1156 :

X Intercepts

: (- \frac{- 0.0191 + 0.000378682}{0.00006}, 0), (\frac{0.0191 + 0.000378682}{0.00006}, 0),

Y Intercepts

: (0, 0.1156)

Vertex of

- 0.00003 x^{2} + 0.0191 x + 0.1156 :

Maximum

(318.33333 \dots, 3.15568 \dots)

Inverse of

- 0.00003 x^{2} + 0.0191 x + 0.1156 : - \frac{- 0.0191 + - 0.00012 x + 0.000378682}{0.00006}, - \frac{- 0.0191 - - 0.00012 x + 0.000378682}{0.00006}

f (x) = x^{3} - 6.5 x^{2} + 11.2 x - 3.1

f (x) = \frac{2 x ^{3} + 4}{x ^{2} + 1}

f (x) = (x^{2} + 1) (x^{3} - 1)

y = \frac{8 x}{x ^{2} + 4}

f (y) = 9 + y^{2}