What is the f(x)=((x+1)(x^2+3x-10))/(x^2+6x+5) ?

The f(x)=((x+1)(x^2+3x-10))/(x^2+6x+5) is

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f(x)=((x+1)(x^2+3x-10))/(x^2+6x+5)

f (x) = \frac{( x + 1 ) ( x ^{2} + 3 x - 10 )}{x ^{2} + 6 x + 5}

Domain : x < - 5 or - 5 < x < - 1 or x > - 1

Range : f (x) < - 7 or - 7 < f (x) < - 3 or f (x) > - 3

X Intercepts : (2, 0), Y Intercepts : (0, - 2)

Asymptotes : Slant y = x - 2

Extreme Points : None

Interval Notation

Domain : (- \infty, - 5) \cup (- 5, - 1) \cup (- 1, \infty)

Range : (- \infty, - 7) \cup (- 7, - 3) \cup (- 3, \infty)

Solution steps

Domain of

\frac{( x + 1 ) ( x ^{2} + 3 x - 10 )}{x ^{2} + 6 x + 5} : x < - 5 or - 5 < x < - 1 or x > - 1

Range of

\frac{( x + 1 ) ( x ^{2} + 3 x - 10 )}{x ^{2} + 6 x + 5} : f (x) < - 7 or - 7 < f (x) < - 3 or f (x) > - 3

Axis interception points of

\frac{( x + 1 ) ( x ^{2} + 3 x - 10 )}{x ^{2} + 6 x + 5} :

X Intercepts

: (2, 0),

Y Intercepts

: (0, - 2)

Asymptotes of

\frac{( x + 1 ) ( x ^{2} + 3 x - 10 )}{x ^{2} + 6 x + 5} :

Slant

: y = x - 2

Extreme Points of

\frac{( x + 1 ) ( x ^{2} + 3 x - 10 )}{x ^{2} + 6 x + 5} :

None

y = \frac{3 ( x ^{2} - 2 ) ^{\frac{1}{2}}}{1 - x}

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f (w) = \frac{7}{w ^{2} - 2 w - 3}

f (x) = \frac{1}{3} e^{x}

f (x) = \frac{8}{x + 7}

What is the f(x)=((x+1)(x^2+3x-10))/(x^2+6x+5) ?
The f(x)=((x+1)(x^2+3x-10))/(x^2+6x+5) is