What is the perpendicular y=9x-3,(-3,-6) ?

The perpendicular y=9x-3,(-3,-6) is y=-1/9 x-19/3

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perpendicular y=9x-3,(-3,-6)

perpendicular

y = 9 x - 3, (- 3, - 6)

y = - \frac{1}{9} x - \frac{19}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 9 x - 3

that passes through

(- 3, - 6)

Find the slope of

y = 9 x - 3 : m = 9

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{9}

Find the line with slope m=

- \frac{1}{9}

and passing through

(- 3, - 6) : y = - \frac{1}{9} x - \frac{19}{3}

y = - \frac{1}{9} x - \frac{19}{3}

(3.3) (1.19)

f (x) = sin^{3} (x)

\frac{x}{3 x - 1}

f (x) = (x - 4) (x - 7)

f (x) = cos (2 (x - π))

What is the perpendicular y=9x-3,(-3,-6) ?
The perpendicular y=9x-3,(-3,-6) is y=-1/9 x-19/3