What is the inverse of f(x)=(2x-3)/(3x-1) ?

The inverse of f(x)=(2x-3)/(3x-1) is (-3+x)/(3x-2)

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inverse of f(x)=(2x-3)/(3x-1)

inverse

f (x) = \frac{2 x - 3}{3 x - 1}

\frac{- 3 + x}{3 x - 2}

Solution steps

y = \frac{2 x - 3}{3 x - 1}

Replace

x

with

y

x = \frac{2 y - 3}{3 y - 1}

Solve for

y, x = \frac{2 y - 3}{3 y - 1}

\frac{- 3 + x}{3 x - 2}

f (x) = \frac{3 - 2 x}{2 x - 5}

f (x) = \frac{x ^{2}}{1 + x ^{2}}

f (x) = \frac{3 - 2 x}{x - 5}

f (x) = \frac{5 - 3 x}{2 x - 3}

f (x) = \frac{5 - 2 x}{4 x - 2}

What is the inverse of f(x)=(2x-3)/(3x-1) ?
The inverse of f(x)=(2x-3)/(3x-1) is (-3+x)/(3x-2)