What is the inverse of f(x)=2pir^2+8pir ?

The inverse of f(x)=2pir^2+8pir is (-8pi+sqrt(64pi^2+8pir))/(4pi),(-8pi-sqrt(64pi^2+8pir))/(4pi)

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inverse of f(x)=2pir^2+8pir

inverse

f (x) = 2 π r^{2} + 8 π r

\frac{- 8 π + 64 π ^{2} + 8 π r}{4 π}, \frac{- 8 π - 64 π ^{2} + 8 π r}{4 π}

Solution steps

x = 2 π r^{2} + 8 π r

Replace

r

with

x

r = 2 π x^{2} + 8 π x

Solve for

x, r = 2 π x^{2} + 8 π x

\frac{- 8 π + 64 π ^{2} + 8 π r}{4 π}, \frac{- 8 π - 64 π ^{2} + 8 π r}{4 π}

f (x) = 2 (3 x + 1) + 4

f (x) = \frac{x}{x - 3}

f (x) = \frac{1}{4} (x + 3)^{2} - 2

\frac{2 x - 3}{3 x - 1}

f (x) = 2 π r^{2} + 12 π r

What is the inverse of f(x)=2pir^2+8pir ?
The inverse of f(x)=2pir^2+8pir is (-8pi+sqrt(64pi^2+8pir))/(4pi),(-8pi-sqrt(64pi^2+8pir))/(4pi)