What is the inverse of 2pir^2+12pir ?

The inverse of 2pir^2+12pir is (-12pi+sqrt(144pi^2+8pir))/(4pi),(-12pi-sqrt(144pi^2+8pir))/(4pi)

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inverse of 2pir^2+12pir

inverse

2 π r^{2} + 12 π r

\frac{- 12 π + 144 π ^{2} + 8 π r}{4 π}, \frac{- 12 π - 144 π ^{2} + 8 π r}{4 π}

Solution steps

y = 2 π r^{2} + 12 π r

Replace

r

with

y

r = 2 π y^{2} + 12 π y

Solve for

y, r = 2 π y^{2} + 12 π y

\frac{- 12 π + 144 π ^{2} + 8 π r}{4 π}, \frac{- 12 π - 144 π ^{2} + 8 π r}{4 π}

f (x) = \frac{x + 2}{- 2 x + 1}

f (x) = e^{x^{2} - 2 x}

f (x) = 3 - 4 - x

2 π r^{2} + 8 π r

f (x) = 2 π x^{2} + 12 π x

What is the inverse of 2pir^2+12pir ?
The inverse of 2pir^2+12pir is (-12pi+sqrt(144pi^2+8pir))/(4pi),(-12pi-sqrt(144pi^2+8pir))/(4pi)