What is the inverse of f(x)=sqrt(2-(x^2)/2) ?

The inverse of f(x)=sqrt(2-(x^2)/2) is sqrt(-2x^2+4),-sqrt(-2x^2+4)

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inverse of f(x)=sqrt(2-(x^2)/2)

inverse

f (x) = 2 - \frac{x ^{2}}{2}

- 2 x^{2} + 4, - - 2 x^{2} + 4

Solution steps

y = 2 - \frac{x ^{2}}{2}

Replace

x

with

y

x = 2 - \frac{y ^{2}}{2}

Solve for

y, x = 2 - \frac{y ^{2}}{2}

- 2 x^{2} + 4, - - 2 x^{2} + 4

f (x) = - 2 (x - 3)^{2} - 6

\frac{3 - 2 x}{2 x - 5}

f (x) = 2 - 3 x^{3}

f (x) = - 2 x^{2} + 8 x - 11

f (x) = \frac{7}{x} + 1

What is the inverse of f(x)=sqrt(2-(x^2)/2) ?
The inverse of f(x)=sqrt(2-(x^2)/2) is sqrt(-2x^2+4),-sqrt(-2x^2+4)