What is the inverse of f(x)=8x^{(2)}-18 ?

The inverse of f(x)=8x^{(2)}-18 is (sqrt(2)sqrt(x+18))/4 ,-(sqrt(2)sqrt(x+18))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=8x^{(2)}-18

inverse

f (x) = 8 x^{(2)} - 18

\frac{2 x + 18}{4}, - \frac{2 x + 18}{4}

Solution steps

y = 8 x^{2} - 18

Replace

x

with

y

x = 8 y^{2} - 18

Solve for

y, x = 8 y^{2} - 18

\frac{2 x + 18}{4}, - \frac{2 x + 18}{4}

\frac{1}{2} (x - 4)^{2} + 1

- 3 (x - 1)^{2} + 2

f (x) = \frac{5 x - 2}{3 x + 1}

f (x) = ln (\frac{e ^{x}}{e ^{x} - 1})

f (x) = \frac{3 x - 1}{2 x + 1}

What is the inverse of f(x)=8x^{(2)}-18 ?
The inverse of f(x)=8x^{(2)}-18 is (sqrt(2)sqrt(x+18))/4 ,-(sqrt(2)sqrt(x+18))/4