What is the inverse of f(x)=x^2-8x+40 ?

The inverse of f(x)=x^2-8x+40 is 4+sqrt(x-24),4-sqrt(x-24)

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inverse of f(x)=x^2-8x+40

inverse

f (x) = x^{2} - 8 x + 40

4 + x - 24, 4 - x - 24

Solution steps

y = x^{2} - 8 x + 40

Replace

x

with

y

x = y^{2} - 8 y + 40

Solve for

y, x = y^{2} - 8 y + 40

4 + x - 24, 4 - x - 24

f (x) = \frac{3 x + 2}{2 - x}

f (x) = 2 3 x + 1 + 4

f (x) = \frac{2 ^{x}}{2 ^{x} + 1}

f (x) = \frac{- 3 x - 11}{2 x - 8}

f (x) = (x^{3} + 25)

What is the inverse of f(x)=x^2-8x+40 ?
The inverse of f(x)=x^2-8x+40 is 4+sqrt(x-24),4-sqrt(x-24)