What is the domain of f(x)=(\sqrt[3]{9x-2})/(x^2+5x-14) ?

The domain of f(x)=(\sqrt[3]{9x-2})/(x^2+5x-14) is x 2

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domain of f(x)=(\sqrt[3]{9x-2})/(x^2+5x-14)

domain

x < - 7 or - 7 < x < 2 or x > 2

Interval Notation

(- \infty, - 7) \cup (- 7, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 7

The function domain

x < - 7 or - 7 < x < 2 or x > 2

y = x^{5}

f (x) = \frac{x ^{2}}{x ^{2} + 10}

f (x) = \frac{6 x - 5}{2}

4 - x + 7

y = \frac{x ^{3}}{3}

What is the domain of f(x)=(\sqrt[3]{9x-2})/(x^2+5x-14) ?
The domain of f(x)=(\sqrt[3]{9x-2})/(x^2+5x-14) is x<-7\lor-7<x<2\lor x>2