What is the inverse of f(x)=5+\sqrt[3]{4/x} ?

The inverse of f(x)=5+\sqrt[3]{4/x} is 4/(x^3-15x^2+75x-125)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=5+\sqrt[3]{4/x}

inverse

\frac{4}{x ^{3} - 15 x ^{2} + 75 x - 125}

Solution steps

Replace

x

with

y

Solve for

\frac{4}{x ^{3} - 15 x ^{2} + 75 x - 125}

2 x + 1

\frac{x ^{2} + 3 x - 4}{x - 1}

f (x) = (x - 1) 2 + 2

f (x) = lo g_{24} (x)

f (x) = x - - x + 1, x < - 4

What is the inverse of f(x)=5+\sqrt[3]{4/x} ?
The inverse of f(x)=5+\sqrt[3]{4/x} is 4/(x^3-15x^2+75x-125)