What is the inverse of ln(sqrt(x^2-2x)) ?

The inverse of ln(sqrt(x^2-2x)) is 1+sqrt(e^{2x)+1},1-sqrt(e^{2x)+1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of ln(sqrt(x^2-2x))

inverse

ln (x^{2} - 2 x)

1 + e^{2 x} + 1, 1 - e^{2 x} + 1

Solution steps

y = ln (x^{2} - 2 x)

Replace

x

with

y

x = ln (y^{2} - 2 y)

Solve for

y, x = ln (y^{2} - 2 y)

1 + e^{2 x} + 1, 1 - e^{2 x} + 1

e^{x^{2} - 2 x}

f (x) = \frac{9 x - 6}{6 x - 7}

f (x) = 4 x - 215

\frac{5 - 2 x}{4 x - 2}

\frac{3 - 2 x}{x - 5}

What is the inverse of ln(sqrt(x^2-2x)) ?
The inverse of ln(sqrt(x^2-2x)) is 1+sqrt(e^{2x)+1},1-sqrt(e^{2x)+1}