What is the inverse of f(x)=\sqrt[3]{3x+1}-6 ?

The inverse of f(x)=\sqrt[3]{3x+1}-6 is (x^3+18x^2+108x+215)/3

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inverse of f(x)=\sqrt[3]{3x+1}-6

inverse

\frac{x ^{3} + 18 x ^{2} + 108 x + 215}{3}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3} + 18 x ^{2} + 108 x + 215}{3}

\frac{3 + x ^{4}}{x ^{2} + x ^{4}}

f (x) = x^{\frac{1}{3}} - 1

\frac{1}{( x + 4 ) ^{2}} - 5

2 (ln (x))^{3}

f (x) = 9 - 5 x^{3}

What is the inverse of f(x)=\sqrt[3]{3x+1}-6 ?
The inverse of f(x)=\sqrt[3]{3x+1}-6 is (x^3+18x^2+108x+215)/3