What is the inverse of f(x)=((x+5))/((2x+1)) ?

The inverse of f(x)=((x+5))/((2x+1)) is (5-x)/(2x-1)

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inverse of f(x)=((x+5))/((2x+1))

inverse

f (x) = \frac{( x + 5 )}{( 2 x + 1 )}

\frac{5 - x}{2 x - 1}

Solution steps

y = \frac{x + 5}{2 x + 1}

Replace

x

with

y

x = \frac{y + 5}{2 y + 1}

Solve for

y, x = \frac{y + 5}{2 y + 1}

\frac{5 - x}{2 x - 1}

f (x) = \frac{2 x}{3} + \frac{3}{5}

\frac{x}{x ^{2} - 9}

f (x) = \frac{4 x + 2}{x - 3}

48 x - 4 x^{2}

f (x) = \frac{5 x - 4}{9 x + 8}

What is the inverse of f(x)=((x+5))/((2x+1)) ?
The inverse of f(x)=((x+5))/((2x+1)) is (5-x)/(2x-1)