What is the inverse of (x+1)/(x^2-5x+6) ?

The inverse of (x+1)/(x^2-5x+6) is (5x+1+sqrt(x^2+14x+1))/(2x),(5x+1-sqrt(x^2+14x+1))/(2x)

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inverse of (x+1)/(x^2-5x+6)

inverse

\frac{x + 1}{x ^{2} - 5 x + 6}

\frac{5 x + 1 + x ^{2} + 14 x + 1}{2 x}, \frac{5 x + 1 - x ^{2} + 14 x + 1}{2 x}

Solution steps

y = \frac{x + 1}{x ^{2} - 5 x + 6}

Replace

x

with

y

x = \frac{y + 1}{y ^{2} - 5 y + 6}

Solve for

y, x = \frac{y + 1}{y ^{2} - 5 y + 6}

\frac{5 x + 1 + x ^{2} + 14 x + 1}{2 x}, \frac{5 x + 1 - x ^{2} + 14 x + 1}{2 x}

sin (x^{3} + 1)

f (x) = lo g_{3} (4 x + 5) - 6

f (x) = 2 π r

\frac{2 x ^{2} - 2}{x ^{2} + 3 x - 4}

f (x) = 2 (5 x - 7) + 3

What is the inverse of (x+1)/(x^2-5x+6) ?
The inverse of (x+1)/(x^2-5x+6) is (5x+1+sqrt(x^2+14x+1))/(2x),(5x+1-sqrt(x^2+14x+1))/(2x)