What is the inverse of f(x)=-3sqrt(x+2)-6,x>=-2 ?

The inverse of f(x)=-3sqrt(x+2)-6,x>=-2 is (4x)/3+(x^2)/9+2

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inverse of f(x)=-3sqrt(x+2)-6,x>=-2

inverse

f (x) = - 3 x + 2 - 6, x \geq - 2

\frac{4 x}{3} + \frac{x ^{2}}{9} + 2

Solution steps

y = - 3 x + 2 - 6

Replace

x

with

y

x = - 3 y + 2 - 6

Solve for

y, x = - 3 y + 2 - 6

\frac{4 x}{3} + \frac{x ^{2}}{9} + 2

f (x) = 6 x + 8 - 5

f (x) = 2 (x - 2)^{2} = 8 (7 + y)

y = (\frac{e ^{x} + 9}{2})^{\frac{1}{3}}

\frac{3 4 + x ^{2}}{2}

f (x) = \frac{2 ^{x} - 1}{2 ^{x} + 1}

What is the inverse of f(x)=-3sqrt(x+2)-6,x>=-2 ?
The inverse of f(x)=-3sqrt(x+2)-6,x>=-2 is (4x)/3+(x^2)/9+2