What is the critical f(x)=9sin(x)+9cos(x) ?

The critical f(x)=9sin(x)+9cos(x) is x= pi/4+2pin,x=(5pi)/4+2pin

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critical f(x)=9sin(x)+9cos(x)

critical points

f (x) = 9 sin (x) + 9 cos (x)

x = \frac{π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

Solution steps

9 sin (x) + 9 cos (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

Identify critical points not in

f (x)

domain

Domain of

9 sin (x) + 9 cos (x) : - \infty < x < \infty

All critical points are in domain

x = \frac{π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

y = x + 5

5 x + 3 y = 9

f (x) = \frac{2 x + 3}{x}

f (x) = 2 x^{2} - 16 x + 1

f (x) = \frac{x ^{2}}{x ^{2} - 25}

What is the critical f(x)=9sin(x)+9cos(x) ?
The critical f(x)=9sin(x)+9cos(x) is x= pi/4+2pin,x=(5pi)/4+2pin