What is the inverse of 2pir^2+16pir ?

The inverse of 2pir^2+16pir is (-16pi+sqrt(256pi^2+8pir))/(4pi),(-16pi-sqrt(256pi^2+8pir))/(4pi)

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inverse of 2pir^2+16pir

inverse

2 π r^{2} + 16 π r

\frac{- 16 π + 256 π ^{2} + 8 π r}{4 π}, \frac{- 16 π - 256 π ^{2} + 8 π r}{4 π}

Solution steps

y = 2 π r^{2} + 16 π r

Replace

r

with

y

r = 2 π y^{2} + 16 π y

Solve for

y, r = 2 π y^{2} + 16 π y

\frac{- 16 π + 256 π ^{2} + 8 π r}{4 π}, \frac{- 16 π - 256 π ^{2} + 8 π r}{4 π}

f (x) = 4 (x - 12) + 2

f (x) = \frac{x}{3} - 9

\frac{7 - 3 x}{2 x - 3}

y = 2 (3^{x}) + 1

f (x) = sin (4 x - 3)

What is the inverse of 2pir^2+16pir ?
The inverse of 2pir^2+16pir is (-16pi+sqrt(256pi^2+8pir))/(4pi),(-16pi-sqrt(256pi^2+8pir))/(4pi)