What is the inverse of f(x)=x^2+4,x<= 0 ?

The inverse of f(x)=x^2+4,x<= 0 is sqrt(x-4),-sqrt(x-4)

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inverse of f(x)=x^2+4,x<= 0

inverse

f (x) = x^{2} + 4, x \leq 0

x - 4, - x - 4

Solution steps

y = x^{2} + 4

Replace

x

with

y

x = y^{2} + 4

Solve for

y, x = y^{2} + 4

x - 4, - x - 4

x^{3} + 5

f (x) = 2 x^{2} - 20 x + 58

3 ln (x + 5) - 2

\frac{2 x}{5 x - 6}

f (x) = \frac{2 x - 3}{6 x - 1}

What is the inverse of f(x)=x^2+4,x<= 0 ?
The inverse of f(x)=x^2+4,x<= 0 is sqrt(x-4),-sqrt(x-4)