What is the inverse of sqrt(e^{x^2-2x)} ?

The inverse of sqrt(e^{x^2-2x)} is 1+sqrt(1+2ln(x)),1-sqrt(1+2ln(x))

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inverse of sqrt(e^{x^2-2x)}

inverse

e^{x^{2} - 2 x}

1 + 1 + 2 ln (x), 1 - 1 + 2 ln (x)

Solution steps

y = e^{x^{2} - 2 x}

Replace

x

with

y

x = e^{y^{2} - 2 y}

Solve for

y, x = e^{y^{2} - 2 y}

1 + 1 + 2 ln (x), 1 - 1 + 2 ln (x)

f (x) = 5 cos (x)

f (x) = \frac{7 x - 2}{4 x + 5}

f (x) = - \frac{3}{8} x^{7}

f (x) = \frac{- 6 x - 4}{- 10 x + 3}

f (x) = lo g_{a} (x)

What is the inverse of sqrt(e^{x^2-2x)} ?
The inverse of sqrt(e^{x^2-2x)} is 1+sqrt(1+2ln(x)),1-sqrt(1+2ln(x))