What is the inverse of f(x)=9x^2-5 ?

The inverse of f(x)=9x^2-5 is (sqrt(x+5))/3 ,-(sqrt(x+5))/3

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inverse of f(x)=9x^2-5

inverse

f (x) = 9 x^{2} - 5

\frac{x + 5}{3}, - \frac{x + 5}{3}

Solution steps

y = 9 x^{2} - 5

Replace

x

with

y

x = 9 y^{2} - 5

Solve for

y, x = 9 y^{2} - 5

\frac{x + 5}{3}, - \frac{x + 5}{3}

f (x) = (\frac{2}{x}) + 5

f (x) = (\frac{1}{x}) + 3

f (x) = 2 - x + 5

f (x) = \frac{3 x}{x - 7}

f (x) = 4 - x^{2} + 12 x + 27

What is the inverse of f(x)=9x^2-5 ?
The inverse of f(x)=9x^2-5 is (sqrt(x+5))/3 ,-(sqrt(x+5))/3