What is the inverse of f(x)=3(x+2)^2+1 ?

The inverse of f(x)=3(x+2)^2+1 is sqrt((x-1)/3)-2,-sqrt((x-1)/3)-2

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inverse of f(x)=3(x+2)^2+1

inverse

f (x) = 3 (x + 2)^{2} + 1

\frac{x - 1}{3} - 2, - \frac{x - 1}{3} - 2

Solution steps

y = 3 (x + 2)^{2} + 1

Replace

x

with

y

x = 3 (y + 2)^{2} + 1

Solve for

y, x = 3 (y + 2)^{2} + 1

\frac{x - 1}{3} - 2, - \frac{x - 1}{3} - 2

f (x) = x^{2} + 8 x + 16

2250 (0.015 - 0.001 x)^{2} + 6000 x

f (x) = \frac{5 x - 3}{2 x + 3}

f (x) = - \frac{9}{2} x + 6

f (x) = 3 x^{2} + 6 x + 15

What is the inverse of f(x)=3(x+2)^2+1 ?
The inverse of f(x)=3(x+2)^2+1 is sqrt((x-1)/3)-2,-sqrt((x-1)/3)-2