What is the inverse of y=3(2^{4x-5}) ?

The inverse of y=3(2^{4x-5}) is (ln((32x)/3))/(4ln(2))

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inverse of y=3(2^{4x-5})

inverse

y = 3 (2^{4 x - 5})

\frac{ln ( \frac{32 x}{3} )}{4 ln ( 2 )}

Solution steps

y = 3 \cdot 2^{4 x - 5}

Replace

x

with

y

x = 3 \cdot 2^{4 y - 5}

Solve for

y, x = 3 2^{4 y - 5}

\frac{ln ( \frac{32 x}{3} )}{4 ln ( 2 )}

f (x) = \frac{- 4 x}{5} + 16

f (x) = 14 x + 4

f (x) = e^{5 x^{2}}

f (x) = \frac{3 x + 2}{x + 1}

4 + ln (x)

What is the inverse of y=3(2^{4x-5}) ?
The inverse of y=3(2^{4x-5}) is (ln((32x)/3))/(4ln(2))