What is the inverse of (2x^2+4x)/(2x+2) ?

The inverse of (2x^2+4x)/(2x+2) is (-2+x+sqrt(x^2+4))/2 ,(-2+x-sqrt(x^2+4))/2

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inverse of (2x^2+4x)/(2x+2)

inverse

\frac{2 x ^{2} + 4 x}{2 x + 2}

\frac{- 2 + x + x ^{2} + 4}{2}, \frac{- 2 + x - x ^{2} + 4}{2}

Solution steps

y = \frac{2 x ^{2} + 4 x}{2 x + 2}

Replace

x

with

y

x = \frac{2 y ^{2} + 4 y}{2 y + 2}

Solve for

y, x = \frac{2 y ^{2} + 4 y}{2 y + 2}

\frac{- 2 + x + x ^{2} + 4}{2}, \frac{- 2 + x - x ^{2} + 4}{2}

f (x) = lo g_{9} (x) + lo g_{9} (12)

f (x) = 75 - \frac{x}{2}

3 - 4 - x

f (x) = 1 - \frac{2 - x}{3}

\frac{2}{x - 4} + 3

What is the inverse of (2x^2+4x)/(2x+2) ?
The inverse of (2x^2+4x)/(2x+2) is (-2+x+sqrt(x^2+4))/2 ,(-2+x-sqrt(x^2+4))/2