What is the inverse of f(x)=(3x-7)/(x+9) ?

The inverse of f(x)=(3x-7)/(x+9) is (-7-9x)/(x-3)

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inverse of f(x)=(3x-7)/(x+9)

inverse

f (x) = \frac{3 x - 7}{x + 9}

\frac{- 7 - 9 x}{x - 3}

Solution steps

y = \frac{3 x - 7}{x + 9}

Replace

x

with

y

x = \frac{3 y - 7}{y + 9}

Solve for

y, x = \frac{3 y - 7}{y + 9}

\frac{- 7 - 9 x}{x - 3}

f (x) = 2 - 4 x

f (x) = 0.05 x + 25

f (x) = - 2 (x + 5)^{2} - 2

f (x) = 3 x^{3} - 6

f (x) = \frac{x + 7}{x + 2}

What is the inverse of f(x)=(3x-7)/(x+9) ?
The inverse of f(x)=(3x-7)/(x+9) is (-7-9x)/(x-3)